Problem on Clocks - TCS Placement Model Questions
For a complete understanding of CLOCKS, Concept of Clocks
For more solved problems and examples, go through Problems on Clocks
TCS NQT Practice questions 7
TCS NQT APTITUDE - Latest Pattern Question 8
TCS Ninja APTITUDE Practice Question 9
TCS NQT Aptitude questions - Model question 10
For a complete understanding of CLOCKS, Concept of Clocks
For more solved problems and examples, go through Problems on Clocks
TCS NQT Questions - Practice Question 1
Between 9 a.m
and 9 p.m of a particular day for how many times are the minute and hour hands
together?
a)10
b)11
c)12
d)13
Answer: B
Explanation: The hands of a clock together (coincide with each other)
once an hour.
From 9 a.m to 9 p.m, there are 12 hours. But between 11 a.m. and 1 p.m.,
the two hands coincide only once at exactly 12'o clock.
Hence between 9 am and 9 pm, the two hands will be
together 11 times.
TCS Ninja Practice questions - Question 2
At what time between 6 O’clock and 7 O’ clock are
the hands of the clock coincide?
a) 6:13
b
)6:36
c) 6:32 $\frac{8}{11}$
$
d) 6:35 $\frac{8}{11}$
Answer: C
Explanation: When the two hands coincide =The angle between the two hands is 00
To find the angle between two hands
θ =|30X
H –$\frac{11}{2}$ x M)|
00 =| 30X 6 -
$\frac{11}{2}$ x M|
ð $\frac{11}{2}$ M = 180
ð M= $\frac{360}{11}$
ð M= 32 $\frac{8}{11}$ minutes
Therefore, the two hands coincide at 6 : 32 $\frac{8}{11}$
TCS NQT - Practice question 3
How many palindromes are there in a clock from noon
to midnight ( For Example 6.06 is a palindrome)?
a)42 b)51 c)53 d)57
a)42 b)51 c)53 d)57
Answer: D
Explanation:
From 12.00 to 1.00, there is only one palindrome
12.21
From 1.00 to 2.00 => 1.01, 1.11, 1.21, 1.31,
1.41, 1.51 => 6 palindromes
From 2.00 to 3.00 => 2.02, 2.12, 2.22, 2.32, 2.42,
2.52 => 6 palindromes
Similarly from 3 to 4, 4 to 5, 5 to 6, 6 to 7, 7 to
8 , 8 to 9 , 9 to 10 => In each hour, there are 6 palindromes
From 10.00 to 11.00 =>10.01 is only palindrome
=> 1 palindrome
From 11.00 to 12.00 => 11.11 is only
palindrome => 1 palindrome
Therefore Number of palindromes = 1 + (9 x 6)+ 1 +
1 =57
TCS NQT Latest Pattern - Question 4
The length of the minute hand of a clock is 5.4 cm.
What is the area covered by this in 10 minutes?
a)14 cm2 b)15.27cm2 c) 16.12 cm2 d)17.732
a)14 cm2 b)15.27cm2 c) 16.12 cm2 d)17.732
Answer: B
Explanation:
Solution: If the minute
hand moves 60 minutes, it makes a circle. Here it is covered only 10
minutes. So it creates a sector.
Length of the minute hand = Radius r = 5.4 cm
The angle made by the minute hand in 10 minutes = 10 x
60 =600
The Area covered by minute hand in 10 minutes = θ/360 x π, x r2
= $\frac{60}{360}$ x $\frac{22}{7}$ x 5.42
= 15.27cm2
TCS Placement
Papers - Prevous Question model 5.
The famous church in the city of Kumbakonam has a big clock tower and is said to
be over 300 years old. Every Monday 10.00 A M the clock is set by John, doing
service in the church. The Clock loses 6 minutes every hour. What will be the
actual time when the faulty clock shows 3 p.m. on Friday?
a. 2:12 AM Saturday b.3.16 PM Friday
a. 2:12 AM Saturday b.3.16 PM Friday
c.
4.54 AM Sunday
d. 3 AM Saturday
Answer: A
Explanation:
Total number of hours from Monday 10 am
to Friday at 3 pm in the faulty clock
= (24 hours x 4 days) + 5 hours = 96 hours + 5 hours = 101 hours.
The clock loses 6 minutes in an hour.
54 minutes of the faulty clock = 60 minutes of the correct clock
101 hours of the faulty clock =$\frac{60}{54}$ x 101 = 112.2 Hours.= 96 Hrs + 16.2 Hrs
Friday 10 am + 16 hrs = Saturday 2am
0.2 x 60 min = 12 min
Therefore, the actual time is Saturday at 2.12 min AM
54 minutes of the faulty clock = 60 minutes of the correct clock
101 hours of the faulty clock =$\frac{60}{54}$ x 101 = 112.2 Hours.= 96 Hrs + 16.2 Hrs
Friday 10 am + 16 hrs = Saturday 2am
0.2 x 60 min = 12 min
Therefore, the actual time is Saturday at 2.12 min AM
TCS NQT Quantitative aptitude Practice Question 6
One-quarter of the time till now from midnight and half of the time remaining from
now up to midnight adds to the present time. What is the present time?
a)8.30 a.m
b)9.36
a.m
c)10.14
a.m d)11.32 a.m
Answer: B
Explanation:
Let the present time = t hrs
Let the present time = t hrs
One-quarter of the time till now from midnight=$\frac{t}{4}$
Half of the time remaining from now up to midnight =(24-t)/2
Hence
=>
$\frac{t}{4}$ + $\frac{24-t}{2}$=t
ð 5t= 48
=> 9.6 hours
The time was 9 hours 36 minutes = 9.36 a.m
TCS NQT Practice questions 7
In a clock the
longer hand is 8cm long and the shorthand is 7 cm long. if the clock runs for 4 days
find out the total distance covered by both the hands
a) 1824 π cm
b)1648Ï€
cm
c)1724Ï€ cm d)2028Ï€ cm
Answer
: B
Explanation:
Short Hand ( Hour hand)
The hour hand makes a full rotation in 12 hours.
One full rotation in 12 hours =>2Ï€r=14Ï€ cm distance is
covered in 12 hours.
In one day(24 hours ), it covers the
distance 2 x 14π = 28 π
In 4 days, the hour hand covers 4 x 28 π=112π cm
Long Hand ( Minute hand)
One full rotation in 1 hour =>2Ï€r=16Ï€ cm distance is
covered in one hour.
In one day ( 24 hours ), the minute hand covers 24 x 16 π=384π cm.
In 4 days, it covers the distance 4 x 384Ï€=1536Ï€ cm.
Total Distance covered
by both hands
For the total, we have 112Ï€+1536Ï€=1648Ï€ cm.
TCS NQT APTITUDE - Latest Pattern Question 8
A circle has 29
points arranged in a clockwise manner from o to 28. A bug moves clockwise manner from 0 to 28. The bug moves clockwise on the circle according to the following rule. If it is at a point i on the circle, it moves clockwise in 1
sec by (1 + r) places, where r is the remainder (possibly 0) when i is divided
by 11. If it starts in 23rd position, at what position will it be after
2012 sec.
a)15th position
b)20th position
c)21st position
d)27th position
Answer : B
Explanation:
After 1st second, it moves
1 + $\frac{23}{11}$ = 1 + 1 = 2, So 25th position
After 2nd second, it moves 1 + $\frac{25}{11}$ = 1 + 3 = 4, So 29th position = 0
After 3rd second, it moves 1 + $\frac{0}{11}$ = 1 + 0 = 1, So 1st position
After 4th second, it moves 1 + 1 = 3rd position
after 5th, 1 + $\frac{3}{11}$ = 4 So 7th
After 6th, 1 + $\frac{7}{11}$ = 8 so 15th
After 7th, 1 + $\frac{15}{11}$ = 5 so 20th
After 8th, 1 + $\frac{20}{11}$ = 10th, So 30th = 1st
So it is on 1st after every 3 + 5n seconds. So it is in 1st position after 2008 seconds (3 + 5 x 401)
Therefore, 20th after 2012 position
After 2nd second, it moves 1 + $\frac{25}{11}$ = 1 + 3 = 4, So 29th position = 0
After 3rd second, it moves 1 + $\frac{0}{11}$ = 1 + 0 = 1, So 1st position
After 4th second, it moves 1 + 1 = 3rd position
after 5th, 1 + $\frac{3}{11}$ = 4 So 7th
After 6th, 1 + $\frac{7}{11}$ = 8 so 15th
After 7th, 1 + $\frac{15}{11}$ = 5 so 20th
After 8th, 1 + $\frac{20}{11}$ = 10th, So 30th = 1st
So it is on 1st after every 3 + 5n seconds. So it is in 1st position after 2008 seconds (3 + 5 x 401)
Therefore, 20th after 2012 position
TCS Ninja APTITUDE Practice Question 9
A clock loses
1% time during the first week and then gains 2% time during the next week. if
the clock was set right at 12 noon on Sunday. What exactly will be the time that the clock will show 14 days from the time it was set right?
a)1.30
pm b)1.42.28
pm c) 1.40.48
pm d)1.52.49
pm
Answer: C
Explanation:
The clock loses 1% time during the first week.
In a week, there are 7 * 24 = 168 hours
In a week, there are 7 * 24 = 168 hours
The clock loses 1% time during the first week, then it will show a time
which is 1% of 168 hours less than 12 Noon at the end of the first week = 1.68
hours less.
Subsequently, the clock gains 2% during the next week. The second week has 168 hours and the clock gains 2% time = 2% of 168 hours = 3.36 hours more than the actual time.
Total gain or loss in 2 weeks = -1.68 + 3.36 = 1.68 hours gain
So the clock will show a time which is 1.68 hours more than 12 Noon after 14 days
Subsequently, the clock gains 2% during the next week. The second week has 168 hours and the clock gains 2% time = 2% of 168 hours = 3.36 hours more than the actual time.
Total gain or loss in 2 weeks = -1.68 + 3.36 = 1.68 hours gain
So the clock will show a time which is 1.68 hours more than 12 Noon after 14 days
1.68 hours = 1 hour and 40.8 minutes = 1 hour 40
minutes and 48 seconds.
i.e. 12 noon + 1 hour 40 minutes and 48 seconds =1 :
40: 48 P.M.
TCS NQT Aptitude questions - Model question 10
On the planet
Oz, there are 8 days in a week- Sunday to Saturday and another day called Oz
day. There are 36 hours in a day and each hour has 90 minutes while each minute
has 60 sec. As on earth, the hour hand covers the dial twice every day. Find
the approximate angle between the hands of a clock on Oz when the time is 12:40
am.
a) 50 b)70 c)89 d)131
a) 50 b)70 c)89 d)131
Answer: C
Explanation: There are 36 hours a day and each hour has 90
minutes and each minute has 60 seconds.
Given time is 12.40
Taking the hour hand into consideration:
The hour hand covers the dial 2 times every day.
So there are 18 hours in the dial.
18 hours = 3600 =>
1 hour = $\frac{360^{0}}{18}$
= 200
In 12 hours, the angle made by the hour hand = 12 x 20
= 2400
Given 1 hour = 90 minutes => 90 minutes =200 => 1 minute = $\frac{20^{0}}{90}$
=> 1 minute = ($\frac{2}{9}$)0
so 40 Min= 40*($\frac{2}{9}$)=8.88(approximately)
The total angel covered by the hour hand is=240+8.88=248.880
Taking the minute hand into consideration:
90 min = 3600 =>
1 min= $\frac{360^{0}}{90^{0}}$
=40
In 40 minutes= 40*4= 1600
The difference between the angle made by the hour hand
and minute hand
= 248.88 – 160 = 88.880= 890 (Approximately)